Iterator base() const; | (until C++17) | |
constexpr Iterator base() const; | (since C++17) |
Returns the underlying base iterator. That is std::reverse_iterator(it).base() == it.
The base iterator refers to the element that is next (from the std::reverse_iterator::iterator_type perspective) to the element the reverse_iterator is currently pointing to. That is &*(rit.base() - 1) == &*rit.
(none).
The underlying iterator.
(none).
#include <iostream>
#include <iterator>
#include <vector>
int main()
{
std::vector<int> v = { 0, 1, 2, 3, 4, 5 };
using RevIt = std::reverse_iterator<std::vector<int>::iterator>;
RevIt r_end(v.begin());
RevIt r_begin(v.end());
for (auto it = r_end.base(); it != r_begin.base(); ++it) {
std::cout << *it << " ";
}
std::cout << "\n";
}Output:
0 1 2 3 4 5
| accesses the pointed-to element (public member function) |
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