Definitions are declarations that fully define the entity introduced by the declaration. Every declaration is a definition, except for the following:
int f(int); // declares, but doesn't define f
extern
storage class specifier or with a language linkage specifier (such as extern "C"
) without an initializer extern const int a; // declares, but doesn't define a extern const int b = 1; // defines b
struct S { int n; // defines S::n static int i; // declares, but doesn't define S::i inline static int x; // defines S::x }; // defines S int S::i; // defines S::i
struct S { static constexpr int x = 42; // implicitly inline, defines S::x }; constexpr int S::x; // declares S::x, not a redefinition | (since C++17) |
struct S; // declares, but doesn't define S class Y f(class T p); // declares, but doesn't define Y and T (and also f and p)
enum Color : int; // declares, but doesn't define Color | (since C++11) |
template<typename T> // declares, but doesn't define T
int f(int x); // declares, but doesn't define f and x int f(int x) { // defines f and x return x+a; }
typedef S S2; // declares, but doesn't define S2 (S may be incomplete)
using S2 = S; // declares, but doesn't define S2 (S may be incomplete) | (since C++11) |
using N::d; // declares, but doesn't define d
| (since C++17) |
| (since C++11) |
extern template f<int, char>; // declares, but doesn't define f<int, char> | (since C++11) |
template<> struct A<int>; // declares, but doesn't define A<int>
An asm declaration does not define any entities, but it is classified as a definition.
Where necessary, the compiler may implicitly define the default constructor, copy constructor, move constructor, copy assignment operator, move assignment operator, and the destructor.
If the definition of any object results in an object of incomplete type, the program is ill-formed.
Only one definition of any variable, function, class type, enumeration type, or template is allowed in any one translation unit (some of these may have multiple declarations, but only one definition is allowed).
One and only one definition of every non-inline function or variable that is odr-used (see below) is required to appear in the entire program (including any standard and user-defined libraries). The compiler is not required to diagnose this violation, but the behavior of the program that violates it is undefined.
For an inline function or inline variable (since C++17), a definition is required in every translation unit where it is odr-used.
One and only one definition of a class is required to appear in any translation unit where the class is used in a way that requires it to be complete.
There can be more than one definition in a program, as long as each definition appears in a different translation unit, of each of the following: class type, enumeration type, inline function with external linkage inline variable with external linkage (since C++17), class template, non-static function template, static data member of a class template, member function of a class template, partial template specialization, as long as all of the following is true:
If all these requirements are satisfied, the program behaves as if there is only one definition in the entire program. Otherwise, the behavior is undefined.
Note: in C, there is no program-wide ODR for types, and even extern declarations of the same variable in different translation units may have different types as long as they are compatible. In C++, the source-code tokens used in declarations of the same type must be the same as described above: if one .cpp file defines struct S { int x; };
and the other .cpp file defines struct S { int y; };
, the behavior of the program that links them together is undefined. This is usually resolved with unnamed namespaces.
Informally, an object is odr-used if its address is taken, or a reference is bound to it, and a function is odr-used if a function call to it is made or its address is taken. If an object or a function is odr-used, its definition must exist somewhere in the program; a violation of that is a link-time error.
struct S { static const int x = 0; // static data member // a definition outside of class is required if it is odr-used }; const int& f(const int& r); int n = b ? (1, S::x) // S::x is not odr-used here : f(S::x); // S::x is odr-used here: a definition is required
Formally,
x
in a potentially-evaluated expression ex
is odr-used unless both of the following are true: x
yields a constant expression that doesn't invoke non-trivial functions struct S { static const int x = 1; }; int f() { return S::x; } // does not odr-use S::x
x
is not an object (that is, x
is a reference) or, if x
is an object, it is one of the potential results of a larger expression e
, where that larger expression is either a discarded-value expression or an lvalue-to-rvalue conversion struct S { static const int x = 1; }; void f() { &S::x; } // discarded-value expression does not odr-use S::x
In the definitions above, potentially-evaluated means the expression is not an unevaluated operand (or its subexpression), such as the operand of sizeof and a set of potential results of an expression e
is a (possibly empty) set of id-expressions that appear within e
, combined as follows:
e
is an id-expression, the expression e
is its only potential result
| (since C++17) |
e
is a class member access expression (e1.e2
or e1->e2
), the potential results of the object expression e1 is included in the set. e
is a pointer-to-member access expression (e1.*e2
or e1->*e2
) whose second operand is a constant expression, the potential results of the object expression e1 are included in the set e
is an expression in parentheses ((e1)
), the potential results of e1
are included in the set e
is a glvalue conditional expression (e1?e2:e3
, where e2 and e3 are glvalues), the union of the potential results of e2
and e3
are both included in the set. e
is a comma expression (e1,e2
), the potential results of e2
are in the set of potential results struct S { static const int a = 1; static const int b = 2; }; int f(bool x) { return x ? S::a : S::b; // x is a part of the subexpression "x" (to the left of ?), // which applies lvalue-to-rvalue conversion, therefore x is not odr-used // S::a and S::b are lvalues, and carry over as "potential results" to the result // of the glvalue conditional // That result is then subject to lvalue-to-rvalue conversion requested // to copy-initialize the return value, therefore S::a and S::b are not odr-used }
T
that is a member or base of another class U
is odr-used by an implicitly-defined copy-assignment or move-assignment functions of U
. In all cases, a constructor selected to copy or move an object is odr-used even if copy elision takes place.
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