Initializes an object from explicit set of constructor arguments.
T object ( arg ); T object | (1) | |
T object { arg }; T object | (2) | (since C++11) |
T ( other ) T | (3) | |
static_cast< T >( other ) | (4) | |
new T(args, ...) | (5) | |
Class::Class() : member(args, ...) {... | (6) | |
[arg](){... | (7) | (since C++11) |
Direct initialization is performed in the following situations:
The effects of direct initialization are:
T is a class type,
| (since C++17) |
T are examined and the best match is selected by overload resolution. The constructor is then called to initialize the object. T is a non-class type, standard conversions are used, if necessary, to convert the value of other to the cv-unqualified version of T. Direct-initialization is more permissive than copy-initialization: copy-initialization only considers non-explicit constructors and non-explicit user-defined conversion functions, while direct-initialization considers all constructors and all user-defined conversion functions.
#include <string>
#include <iostream>
#include <memory>
struct Foo {
int mem;
explicit Foo(int n) : mem(n) {}
};
int main()
{
std::string s1("test"); // constructor from const char*
std::string s2(10, 'a');
std::unique_ptr<int> p(new int(1)); // OK: explicit constructors allowed
// std::unique_ptr<int> p = new int(1); // error: constructor is explicit
Foo f(2); // f is direct-initialized:
// constructor parameter n is copy-initialized from the rvalue 2
// f.mem is direct-initialized from the parameter n
// Foo f2 = 2; // error: constructor is explicit
std::cout << s1 << ' ' << s2 << ' ' << *p << ' ' << f.mem << '\n';
}Output:
test aaaaaaaaaa 1 2
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