Initializes an object from explicit set of constructor arguments.
T object ( arg ); T object | (1) | |
T object { arg }; T object | (2) | (since C++11) |
T ( other ) T | (3) | |
static_cast< T >( other ) | (4) | |
new T( args, ...) | (5) | |
Class:: Class() : member( args, ...) {... | (6) | |
[ arg](){... | (7) | (since C++11) |
Direct initialization is performed in the following situations:
The effects of direct initialization are:
T
is a class type,
| (since C++17) |
T
are examined and the best match is selected by overload resolution. The constructor is then called to initialize the object. T
is a non-class type, standard conversions are used, if necessary, to convert the value of other to the cv-unqualified version of T
. Direct-initialization is more permissive than copy-initialization: copy-initialization only considers non-explicit constructors and non-explicit user-defined conversion functions, while direct-initialization considers all constructors and all user-defined conversion functions.
#include <string> #include <iostream> #include <memory> struct Foo { int mem; explicit Foo(int n) : mem(n) {} }; int main() { std::string s1("test"); // constructor from const char* std::string s2(10, 'a'); std::unique_ptr<int> p(new int(1)); // OK: explicit constructors allowed // std::unique_ptr<int> p = new int(1); // error: constructor is explicit Foo f(2); // f is direct-initialized: // constructor parameter n is copy-initialized from the rvalue 2 // f.mem is direct-initialized from the parameter n // Foo f2 = 2; // error: constructor is explicit std::cout << s1 << ' ' << s2 << ' ' << *p << ' ' << f.mem << '\n'; }
Output:
test aaaaaaaaaa 1 2
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