Assignment operators modify the value of the object.
Operator name  Syntax  Overloadable  Prototype examples (for class T ) 


Inside class definition  Outside class definition  
simple assignment  a = b  Yes  T& T::operator =(const T2& b);  N/A 
addition assignment  a += b  Yes  T& T::operator +=(const T2& b);  T& operator +=(T& a, const T2& b); 
subtraction assignment  a = b  Yes  T& T::operator =(const T2& b);  T& operator =(T& a, const T2& b); 
multiplication assignment  a *= b  Yes  T& T::operator *=(const T2& b);  T& operator *=(T& a, const T2& b); 
division assignment  a /= b  Yes  T& T::operator /=(const T2& b);  T& operator /=(T& a, const T2& b); 
modulo assignment  a %= b  Yes  T& T::operator %=(const T2& b);  T& operator %=(T& a, const T2& b); 
bitwise AND assignment  a &= b  Yes  T& T::operator &=(const T2& b);  T& operator &=(T& a, const T2& b); 
bitwise OR assignment  a = b  Yes  T& T::operator =(const T2& b);  T& operator =(T& a, const T2& b); 
bitwise XOR assignment  a ^= b  Yes  T& T::operator ^=(const T2& b);  T& operator ^=(T& a, const T2& b); 
bitwise left shift assignment  a <<= b  Yes  T& T::operator <<=(const T2& b);  T& operator <<=(T& a, const T2& b); 
bitwise right shift assignment  a >>= b  Yes  T& T::operator >>=(const T2& b);  T& operator >>=(T& a, const T2& b); 
Notes

copy assignment operator replaces the contents of the object a
with a copy of the contents of b
(b
is not modified). For class types, this is a special member function, described in copy assignment operator.
move assignment operator replaces the contents of the object a
with the contents of b
, avoiding copying if possible (b
may be modified). For class types, this is a special member function, described in move assignment operator. (since C++11).
For nonclass types, copy and move assignment are indistinguishable and are referred to as direct assignment.
compound assignment operators replace the contents of the object a
with the result of a binary operation between the previous value of a
and the value of b
.
For every type T
, the following function signatures participate in overload resolution:
T*& operator=(T*&, T*);  
T*volatile & operator=(T*volatile &, T*); 
For every enumeration or pointer to member type T
, optionally volatilequalified, the following function signature participates in overload resolution:
T& operator=(T&, T ); 
For every pair A1 and A2, where A1 is an arithmetic type (optionally volatilequalified) and A2 is a promoted arithmetic type, the following function signature participates in overload resolution:
A1& operator=(A1&, A2); 
For expressions E1 of any scalar type T
, the following additional forms of the builtin assignment expression are allowed:
E1 = {}  (since C++11)  
E1 = {E2}  (since C++11) 
Note: the above includes all nonclass types except reference types, array types, function types, and the type void
, which are not directly assignable.
The direct assignment operator expects a modifiable lvalue as its left operand and an rvalue expression or a bracedinitlist (since C++11) as its right operand, and returns an lvalue identifying the left operand after modification.
For nonclass types, the right operand is first implicitly converted to the cvunqualified type of the left operand, and then its value is copied into the object identified by left operand.
When the left operand has reference type, the assignment operator modifies the referredto object.
If the left and the right operands identify overlapping objects, the behavior is undefined (unless the overlap is exact and the type is the same).
If the right operand is a bracedinitlist.
 (since C++11) 
#include <iostream> int main() { int n = 0; // not an assignment n = 1; // direct assignment std::cout << n << ' '; n = {}; // zeroinitialization, then assignment std::cout << n << ' '; n = 'a'; // integral promotion, then assignment std::cout << n << ' '; n = {'b'}; // explicit cast, then assignment std::cout << n << ' '; n = 1.0; // floatingpoint conversion, then assignment std::cout << n << ' '; // n = {1.0}; // compiler error (narrowing conversion) int& r = n; // not an assignment int* p; r = 2; // assignment through reference std::cout << n << '\n'; p = &n; // direct assignment p = nullptr; // nullpointer conversion, then assignment struct {int a; std::string s;} obj; obj = {1, "abc"}; // assignment from a bracedinitlist std::cout << obj.a << ':' << obj.s << '\n'; }
Output:
1 0 97 98 1 2 1:abc
For every pair A1 and A2, where A1 is an arithmetic type (optionally volatilequalified) and A2 is a promoted arithmetic type, the following function signatures participate in overload resolution:
A1& operator*=(A1&, A2);  
A1& operator/=(A1&, A2);  
A1& operator+=(A1&, A2);  
A1& operator=(A1&, A2); 
For every pair I1 and I2, where I1 is an integral type (optionally volatilequalified) and I2 is a promoted integral type, the following function signatures participate in overload resolution:
I1& operator%=(I1&, I2);  
I1& operator<<=(I1&, I2);  
I1& operator>>=(I1&, I2);  
I1& operator&=(I1&, I2);  
I1& operator^=(I1&, I2);  
I1& operator=(I1&, I2); 
For every optionally cvqualified object type T
, the following function signatures participate in overload resolution:
T*& operator+=(T*&, std::ptrdiff_t);  
T*& operator=(T*&, std::ptrdiff_t);  
T*volatile & operator+=(T*volatile &, std::ptrdiff_t);  
T*volatile & operator=(T*volatile &, std::ptrdiff_t); 
The behavior of every builtin compoundassignment expression E1 op= E2
(where E1 is a modifiable lvalue expression and E2 is an rvalue expression or a bracedinitlist (since C++11)) is exactly the same as the behavior of the expression E1 = E1 op E2
, except that the expression E1
is evaluated only once and that it behaves as a single operation with respect to indeterminatelysequenced function calls (e.g. in f(a += b, g())
, the += is either not started at all or is completed as seen from inside g()
).
Common operators  

assignment  increment decrement  arithmetic  logical  comparison  member access  other 







Special operators  

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