Defined in header <type_traits> | ||
---|---|---|
template<class... B> struct disjunction; | (1) | (since C++17) |
Forms the logical disjunction of the type traits B...
, effectively performing a logical or on the sequence of traits.
The specialization std::disjunction<B1, ..., BN>
has a public and unambiguous base that is.
sizeof...(B) == 0
, std::false_type
; otherwise Bi
in B1, ..., BN
for which bool(Bi::value) == true
, or BN
if there is no such type. The member names of the base class, other than disjunction
and operator=
, are not hidden and are unambiguously available in disjunction
.
Disjunction is short-circuiting: if there is a template type argument Bi
with bool(Bi::value) != false
, then instantiating disjunction<B1, ..., BN>::value
does not require the instantiation of Bj::value
for j > i
.
B... | - | every template argument Bi for which Bi::value is instantiated must be usable as a base class and define member value that is convertible to bool |
template<class... B> inline constexpr bool disjunction_v = disjunction<B...>::value; | (since C++17) |
template<class...> struct disjunction : std::false_type { }; template<class B1> struct disjunction<B1> : B1 { }; template<class B1, class... Bn> struct disjunction<B1, Bn...> : std::conditional_t<bool(B1::value), B1, disjunction<Bn...>> { }; |
A specialization of disjunction
does not necessarily inherit from of either std::true_type
or std::false_type
: it simply inherits from the first B
whose ::value
, explicitly converted to bool
, is true, or from the very last B when all of them convert to false. For example, std::disjunction<std::integral_constant<int, 2>, std::integral_constant<int, 4>>::value
is 2
.
The short-circuit instantiation differentiates disjunction
from fold expressions: a fold expression like (... || Bs::value)
instantiates every B
in Bs
, while std::disjunction_v<Bs...>
stops instantiation once the value can be determined. This is particularly useful if the later type is expensive to instantiate or can cause a hard error when instantiated with the wrong type.
#include <iostream> #include <type_traits> using result0 = std::disjunction<std::bool_constant<false>, std::bool_constant<false>, std::bool_constant<false>>; using result1 = std::disjunction<std::bool_constant<true>, std::bool_constant<false>, std::bool_constant<false>>; int main() { std::cout << std::boolalpha; std::cout << result0::value << '\n'; std::cout << result1::value << '\n'; }
Output:
false true
(C++17) | logical NOT metafunction (class template) |
(C++17) | variadic logical AND metafunction (class template) |
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