Functions that work on sets.
MapSet is the “go to” set data structure in Elixir. A set can be constructed using MapSet.new/0:
iex> MapSet.new
#MapSet<[]> A set can contain any kind of elements, and elements in a set don’t have to be of the same type. By definition, sets can’t contain duplicate elements: when inserting an element in a set where it’s already present, the insertion is simply a no-op.
iex> map_set = MapSet.new
iex> MapSet.put(map_set, "foo")
#MapSet<["foo"]>
iex> map_set |> MapSet.put("foo") |> MapSet.put("foo")
#MapSet<["foo"]> A MapSet is represented internally using the %MapSet{} struct. This struct can be used whenever there’s a need to pattern match on something being a MapSet:
iex> match?(%MapSet{}, MapSet.new())
true Note that, however, the struct fields are private and must not be accessed directly; use the functions in this module to perform operations on sets.
MapSets can also be constructed starting from other collection-type data structures: for example, see MapSet.new/1 or Enum.into/2.
Deletes value from map_set
Returns a set that is map_set1 without the members of map_set2
Checks if map_set1 and map_set2 have no members in common
Checks if two sets are equal
Returns a set containing only members that map_set1 and map_set2 have in common
Checks if map_set contains value
Returns a new set
Creates a set from an enumerable
Creates a set from an enumerable via the transformation function
Inserts value into map_set if map_set doesn’t already contain it
Returns the number of elements in map_set
Checks if map_set1’s members are all contained in map_set2
Converts map_set to a list
Returns a set containing all members of map_set1 and map_set2
t() :: t(term())
t(value)
value() :: term()
delete(t(val1), val2) :: t(val1) when val1: value(), val2: value()
Deletes value from map_set.
Returns a new set which is a copy of map_set but without value.
iex> map_set = MapSet.new([1, 2, 3])
iex> MapSet.delete(map_set, 4)
#MapSet<[1, 2, 3]>
iex> MapSet.delete(map_set, 2)
#MapSet<[1, 3]> difference(t(val1), t(val2)) :: t(val1) when val1: value(), val2: value()
Returns a set that is map_set1 without the members of map_set2.
iex> MapSet.difference(MapSet.new([1, 2]), MapSet.new([2, 3, 4]))
#MapSet<[1]> disjoint?(t(), t()) :: boolean()
Checks if map_set1 and map_set2 have no members in common.
iex> MapSet.disjoint?(MapSet.new([1, 2]), MapSet.new([3, 4]))
true
iex> MapSet.disjoint?(MapSet.new([1, 2]), MapSet.new([2, 3]))
false equal?(t(), t()) :: boolean()
Checks if two sets are equal.
The comparison between elements must be done using ===.
iex> MapSet.equal?(MapSet.new([1, 2]), MapSet.new([2, 1, 1]))
true
iex> MapSet.equal?(MapSet.new([1, 2]), MapSet.new([3, 4]))
false intersection(t(val), t(val)) :: t(val) when val: value()
Returns a set containing only members that map_set1 and map_set2 have in common.
iex> MapSet.intersection(MapSet.new([1, 2]), MapSet.new([2, 3, 4]))
#MapSet<[2]>
iex> MapSet.intersection(MapSet.new([1, 2]), MapSet.new([3, 4]))
#MapSet<[]> member?(t(), value()) :: boolean()
Checks if map_set contains value.
iex> MapSet.member?(MapSet.new([1, 2, 3]), 2)
true
iex> MapSet.member?(MapSet.new([1, 2, 3]), 4)
false new() :: t()
Returns a new set.
iex> MapSet.new
#MapSet<[]> new(Enum.t()) :: t()
Creates a set from an enumerable.
iex> MapSet.new([:b, :a, 3])
#MapSet<[3, :a, :b]>
iex> MapSet.new([3, 3, 3, 2, 2, 1])
#MapSet<[1, 2, 3]> new(Enum.t(), (term() -> val)) :: t(val) when val: value()
Creates a set from an enumerable via the transformation function.
iex> MapSet.new([1, 2, 1], fn x -> 2 * x end)
#MapSet<[2, 4]> put(t(val), new_val) :: t(val | new_val) when val: value(), new_val: value()
Inserts value into map_set if map_set doesn’t already contain it.
iex> MapSet.put(MapSet.new([1, 2, 3]), 3)
#MapSet<[1, 2, 3]>
iex> MapSet.put(MapSet.new([1, 2, 3]), 4)
#MapSet<[1, 2, 3, 4]> size(t()) :: non_neg_integer()
Returns the number of elements in map_set.
iex> MapSet.size(MapSet.new([1, 2, 3]))
3 subset?(t(), t()) :: boolean()
Checks if map_set1’s members are all contained in map_set2.
This function checks if map_set1 is a subset of map_set2.
iex> MapSet.subset?(MapSet.new([1, 2]), MapSet.new([1, 2, 3]))
true
iex> MapSet.subset?(MapSet.new([1, 2, 3]), MapSet.new([1, 2]))
false to_list(t(val)) :: [val] when val: value()
Converts map_set to a list.
iex> MapSet.to_list(MapSet.new([1, 2, 3]))
[1, 2, 3] union(t(val1), t(val2)) :: t(val1 | val2) when val1: value(), val2: value()
Returns a set containing all members of map_set1 and map_set2.
iex> MapSet.union(MapSet.new([1, 2]), MapSet.new([2, 3, 4]))
#MapSet<[1, 2, 3, 4]>
© 2012 Plataformatec
Licensed under the Apache License, Version 2.0.
https://hexdocs.pm/elixir/1.6.0/MapSet.html