return
statements to either always or never specify values (consistent-return)Unlike statically-typed languages which enforce that a function returns a specified type of value, JavaScript allows different code paths in a function to return different types of values.
A confusing aspect of JavaScript is that a function returns undefined
if any of the following are true:
return
statement before it exitsreturn
which does not specify a value explicitlyreturn undefined
return void
followed by an expression (for example, a function call)return
followed by any other expression which evaluates to undefined
If any code paths in a function return a value explicitly but some code path do not return a value explicitly, it might be a typing mistake, especially in a large function. In the following example:
true
undefined
implicitlyfunction doSomething(condition) { if (condition) { return true; } else { return; } }
This rule requires return
statements to either always or never specify values. This rule ignores function definitions where the name begins with an uppercase letter, because constructors (when invoked with the new
operator) return the instantiated object implicitly if they do not return another object explicitly.
Examples of incorrect code for this rule:
/*eslint consistent-return: "error"*/ function doSomething(condition) { if (condition) { return true; } else { return; } } function doSomething(condition) { if (condition) { return true; } }
Examples of correct code for this rule:
/*eslint consistent-return: "error"*/ function doSomething(condition) { if (condition) { return true; } else { return false; } } function Foo() { if (!(this instanceof Foo)) { return new Foo(); } this.a = 0; }
This rule has an object option:
"treatUndefinedAsUnspecified": false
(default) always either specify values or return undefined
implicitly only."treatUndefinedAsUnspecified": true
always either specify values or return undefined
explicitly or implicitly.Examples of incorrect code for this rule with the default { "treatUndefinedAsUnspecified": false }
option:
/*eslint consistent-return: ["error", { "treatUndefinedAsUnspecified": false }]*/ function foo(callback) { if (callback) { return void callback(); } // no return statement } function bar(condition) { if (condition) { return undefined; } // no return statement }
Examples of incorrect code for this rule with the { "treatUndefinedAsUnspecified": true }
option:
/*eslint consistent-return: ["error", { "treatUndefinedAsUnspecified": true }]*/ function foo(callback) { if (callback) { return void callback(); } return true; } function bar(condition) { if (condition) { return undefined; } return true; }
Examples of correct code for this rule with the { "treatUndefinedAsUnspecified": true }
option:
/*eslint consistent-return: ["error", { "treatUndefinedAsUnspecified": true }]*/ function foo(callback) { if (callback) { return void callback(); } // no return statement } function bar(condition) { if (condition) { return undefined; } // no return statement }
If you want to allow functions to have different return
behavior depending on code branching, then it is safe to disable this rule.
This rule was introduced in ESLint 0.4.0.
© JS Foundation and other contributors
Licensed under the MIT License.
https://eslint.org/docs/rules/consistent-return