numpy.ma.is_masked(x) [source]
Determine whether input has masked values.
Accepts any object as input, but always returns False unless the input is a MaskedArray containing masked values.
| Parameters: |
x : array_like Array to check for masked values. |
|---|---|
| Returns: |
result : bool True if |
>>> import numpy.ma as ma
>>> x = ma.masked_equal([0, 1, 0, 2, 3], 0)
>>> x
masked_array(data = [-- 1 -- 2 3],
mask = [ True False True False False],
fill_value=999999)
>>> ma.is_masked(x)
True
>>> x = ma.masked_equal([0, 1, 0, 2, 3], 42)
>>> x
masked_array(data = [0 1 0 2 3],
mask = False,
fill_value=999999)
>>> ma.is_masked(x)
False
Always returns False if x isn’t a MaskedArray.
>>> x = [False, True, False] >>> ma.is_masked(x) False >>> x = 'a string' >>> ma.is_masked(x) False
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https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.ma.is_masked.html