numpy.prod(a, axis=None, dtype=None, out=None, keepdims=<class numpy._globals._NoValue>)
[source]
Return the product of array elements over a given axis.
Parameters: |
a : array_like Input data. axis : None or int or tuple of ints, optional Axis or axes along which a product is performed. The default, axis=None, will calculate the product of all the elements in the input array. If axis is negative it counts from the last to the first axis. New in version 1.7.0. If axis is a tuple of ints, a product is performed on all of the axes specified in the tuple instead of a single axis or all the axes as before. dtype : dtype, optional The type of the returned array, as well as of the accumulator in which the elements are multiplied. The dtype of out : ndarray, optional Alternative output array in which to place the result. It must have the same shape as the expected output, but the type of the output values will be cast if necessary. keepdims : bool, optional If this is set to True, the axes which are reduced are left in the result as dimensions with size one. With this option, the result will broadcast correctly against the input array. If the default value is passed, then |
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Returns: |
product_along_axis : ndarray, see An array shaped as |
See also
ndarray.prod
numpy.doc.ufuncs
Arithmetic is modular when using integer types, and no error is raised on overflow. That means that, on a 32-bit platform:
>>> x = np.array([536870910, 536870910, 536870910, 536870910]) >>> np.prod(x) #random 16
The product of an empty array is the neutral element 1:
>>> np.prod([]) 1.0
By default, calculate the product of all elements:
>>> np.prod([1.,2.]) 2.0
Even when the input array is two-dimensional:
>>> np.prod([[1.,2.],[3.,4.]]) 24.0
But we can also specify the axis over which to multiply:
>>> np.prod([[1.,2.],[3.,4.]], axis=1) array([ 2., 12.])
If the type of x
is unsigned, then the output type is the unsigned platform integer:
>>> x = np.array([1, 2, 3], dtype=np.uint8) >>> np.prod(x).dtype == np.uint True
If x
is of a signed integer type, then the output type is the default platform integer:
>>> x = np.array([1, 2, 3], dtype=np.int8) >>> np.prod(x).dtype == np.int True
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https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.prod.html