r.branch(test, true_action[, test2, test2_action, ...], false_action) → any test.branch(true_action[, test2, test2_action, ...], false_action) → any
Perform a branching conditional equivalent to if-then-else
.
The branch
command takes 2n+1 arguments: pairs of conditional expressions and commands to be executed if the conditionals return any value but false
or null
(i.e., “truthy” values), with a final “else” command to be evaluated if all of the conditionals are false
or null
.
You may call branch
infix style on the first test. (See the second example for an illustration.)
r.branch(test1, val1, test2, val2, elseval)
is the equivalent of the Java statement
if (test1) { return val1; } else if (test2) { return val2; } else { return elseval; }
Example: Test the value of x.
int x = 10; r.branch(r.expr(x).gt(5), "big", "small").run(conn); // Result: "big"
Example: As above, infix-style.
int x = 10; r.expr(x).gt(5).branch("big", "small").run(conn); // Result: "big"
Example: Categorize heroes by victory counts.
r.table("marvel").map(hero -> r.branch( hero.g("victories").gt(100), hero.g("name").add(" is a superhero"), hero.g("victories").gt(10), hero.g("name").add(" is a hero"), hero.g("name").add(" is very nice") )).run(conn);
If the documents in the table marvel
are:
[ { "name": "Iron Man", "victories": 214 }, { "name": "Jubilee", "victories": 49 }, { "name": "Slava", "victories": 5 } ]
The results will be:
[ "Iron Man is a superhero", "Jubilee is a hero", "Slava is very nice" ]
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